Get latest date from list of dates python

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WebHere's a more flexible way to rename columns within the aggregate function: agg (date_min= ('date', 'min'), date_max= ('date', 'max')) – butterflyeffect Mar 7 at 22:57 Add a comment 26 Simple code can be df.groupby ( [key_field]).agg ( {'time_field': [np.min,np.max]}) where key_field here can be event_id and time_field can be timestamp … WebApr 11, 2024 · Method #1 : Using min () + dictionary comprehension + abs () In this, a difference of each date with a given date is computed as key and date as a value using …

How to get list of business dates given month and year in Python ...

WebMar 9, 2024 · How to create a list of dates within a date range in Python Example: create a list of dates within a range of dates Example 2: Create a list of the next 7 dates starting … Web29 rows · Apr 13, 2024 · Example Get your own Python Server. Create a date object: import datetime. x = datetime.datetime (2024, 5, 17) print(x) Try it Yourself ». The … mn st hwy patrol

Finding Min/Max Date with List Comprehension in Python

You can use datetime module and sorted(iterable[, cmp[, key[, reverse]]]) function with reverse = true and key argument to convent string into datetime object , at zero index you will get latest date check following code (read comments): >>> from datetime import datetime >>> dates = ['1985-4-5', '1985-2-9', '1983-2-2', '1998-1-12' ] >>> sorted( ... WebDec 15, 2024 · Create the List of Range of Dates Manually in Python. With the help of for loop and timedelta(), we can generate the list manually.timedelta() is a function defined under the datetime library. Here delta means difference. With its help, we can add or subtract delta with a date to get the next or previous date, respectively. injectable medication for bipolar

datetime - Creating a range of dates in Python - Stack Overflow

python - How to filter a list containing dates according to the …

WebMar 2, 2011 · How to sort the below array of dates on python 2.4 timestamps = ['2011-06-2', '2011-08-05', '2011-02-04', '2010-1-14', '2010-12-13', '2010-1-12', '2010-2-11', '2010-2-07', '2010-12-02', '2011-11-30', '2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16'] python Share Improve this question Follow asked Mar 2, 2011 at 11:29 Rajeev 44.2k 76 … WebJan 20, 2016 · import datetime start_date = datetime.datetime (2015, 10, 02) end_date = datetime.datetime (2024, 03, 04) def nextday (): global start_date start_date += datetime.timedelta (days=1) return min (start_date, end_date) >>> start_date datetime.datetime (2015, 10, 2, 0, 0) >>> nextday () datetime.datetime (2015, 10, 3, 0, … mns towelsWebJul 7, 2011 · 1 Answer Sorted by: 3 You can use max () but you have to use the key param to convert the date string to true dates so they compare correctly, e.g.: In []: from … mns towing

"WebAug 1, 2015 · Just use dates.append (d) instead of dates.append (datetime.datetime.strftime (d,'%Y-%m-%d')) to get a list of datetime.date objects instead of strings. Reversing a list is pretty straight-forward in Python: dates = dates [::-1] After the above, dates [0] will be '2024-07-06'. Share Follow edited Jun 7, 2024 at 16:38 … " - Get latest date from list of dates python

Get latest date from list of dates python

Select the most recent date from a table using Python/arcpy

WebSep 13, 2024 · dateList = [] for row in table.select ("tbody tr"): data = [td.text for td in row.select ("td")] d = datetime.strptime (data [0], '%b %d, %Y').date () dateList = dateList + [d, ] print max (dateList) Share Improve this answer Follow edited Sep 13, 2024 at 2:18 answered Sep 13, 2024 at 1:35 Chai Ang 464 1 6 11 Thanks for the reply mate. WebJan 23, 2024 · First you need to convert the installed_date column to datetime: df ['installed_date'] = pd.to_datetime (df ['installed_date']) Then you can use one of the options below: Option 1: sort the values on installed_date then drop_duplicates keeping only the last row per software_id.

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WebSELECT TOP 1 * FROM foo ORDER BY Dates DESC. Will return one result with the latest date. SELECT * FROM foo WHERE foo.Dates = (SELECT MAX (Dates) FROM foo) Will return all results that have the same maximum date, … WebJul 13, 2015 · You could use datetime library to convert your date strings into datetime objects so they can be compared. Then you can simply use list comprehension to produce a list of the required dates.

WebApr 13, 2015 · Use the built-in min () / max () functions: earliest = min (timestamp) latest = max (timestamp) As side note I suggest you to build the list with the list comprehension: … WebNov 2, 2012 · Retrieve the third latest date on the sorted list using sorted_dates [-3]. We can get the year, month, and date in the following way: (d, m, y) = "11/02/2012".split ('/') Then, simply reverse the tuple, and run sort. Share Improve this answer Follow edited Jul 15, 2024 at 9:07 answered Jul 15, 2024 at 8:59 Mateen Ulhaq 23.4k 16 91 132

WebMay 2, 2024 · This method is only advisable for large ranges where you believe the date you require is near the start of your DatetimeIndex. x = pd.Timestamp ('2024-05-04') res = next ( (i for i, j in enumerate (dates_list) if j == x), None) Share Improve this answer Follow answered May 2, 2024 at 12:53 jpp 157k 33 273 331 Add a comment Your Answer WebNov 5, 2014 · Use search cursor to iterate through layer and assign date values to list. Use the select layer by attribute method on feature layer with value from step 2. In the spirit of …

WebJan 15, 2015 · In your case, given the list Dates, you can make a new list like this: last_dates = [datetime.datetime (date.year, date.month, calendar.monthrange (date.year, date.month) [1]) for date in Dates] Share Follow edited Sep 16, 2015 at 15:53 answered Sep 16, 2015 at 15:18 Michael Laszlo 11.9k 2 29 46

WebOct 20, 2024 · I'm trying to obtain a list of dates (in datetime format) for any given month and year in Python. ie. if month is August or 8 and year is 2024, my expected list would be something like this: list = [2024-08-01, 2024-08-02, 2024-08-05, .....] (as you can see, I'd need the weekends to not show up) No need to worry about any holiday assumptions! mn storm swimmingWebOct 8, 2011 · DateTime latestDate = myCollection.Where (r => r.ExpirationDate.HasValue) .Max (r => r.ExpirationDate) .Value; This will not cover the case of an empty collection or a collection with only null ExpirationDates. Depending on your earlier logic, checking myCollection.Any (r => r.ExpirationDate.HasValue) injectable medication for bipolar disorderWebDec 15, 2024 · Using Pandas to Create a List of Range of Dates in Python We will use the date_range () function of pandas in which we will pass the start date and the number of … mn storm snow totalsWebMar 23, 2024 · Creating a list of dates using Python Loop In this, we perform a similar task as the above function, using a generator to perform the task of Date successions. … injectable medication for dementiaWebJun 14, 2009 · You can write a generator function that returns date objects starting from today: import datetime def date_generator (): from_date = datetime.datetime.today () while True: yield from_date from_date = from_date - datetime.timedelta (days=1) This generator returns dates starting from today and going backwards one day at a time. injectable medication for asthmaWebJul 28, 2014 · Just use min () or max () to find the earliest or latest dates: earliest_date = min (snapshots) lastest_date = max (snapshots) Of course, if your list of dates is already sorted, use: earliest_date = snapshots [0] lastest_date = snapshots [-1] Demo: mns trackingWebHow to group values of pandas dataframe and select the latest(by date) from each group? For example, given a dataframe sorted by date: id product date 0 220 6647 2014-09-01 1 220 6647 2014-09-03 2 220 6647 2014-10-16 3 826 3380 2014-11-11 4 826 3380 2014-12-09 5 826 3380 2015-05-19 6 901 4555 2014-09-01 7 901 4555 2014-10-05 8 901 4555 … injectable medication for diarrhea